<Dd> Z eq = R + j X = (R 1 + R 2 + ⋯ + R n) + j (X 1 + X 2 + ⋯ + X n) (\ displaystyle \ Z_ (\ text (eq)) = R + jX = (R_ (1) + R_ (2) + \ cdots + R_ (n)) + j (X_ (1) + X_ (2) + \ cdots + X_ (n)) \ quad) </Dd> <P> For components connected in parallel, the voltage across each circuit element is the same; the ratio of currents through any two elements is the inverse ratio of their impedances . </P> <P> Hence the inverse total impedance is the sum of the inverses of the component impedances: </P> <Dl> <Dd> 1 Z eq = 1 Z 1 + 1 Z 2 + ⋯ + 1 Z n (\ displaystyle (\ frac (1) (Z_ (\ text (eq)))) = (\ frac (1) (Z_ (1))) + (\ frac (1) (Z_ (2))) + \ cdots + (\ frac (1) (Z_ (n)))) </Dd> </Dl>

Explain why is the impedance of inductor j omega l