<Dl> <Dd> C = 2 π r = π d . (\ displaystyle C = 2 \ pi r = \ pi d. \,) </Dd> </Dl> <Dd> C = 2 π r = π d . (\ displaystyle C = 2 \ pi r = \ pi d. \,) </Dd> <P> As proved by Archimedes, in his Measurement of a Circle, the area enclosed by a circle is equal to that of a triangle whose base has the length of the circle's circumference and whose height equals the circle's radius, which comes to π multiplied by the radius squared: </P> <Dl> <Dd> A r e a = π r 2 . (\ displaystyle \ mathrm (Area) = \ pi r ^ (2). \,) </Dd> </Dl>

How do you find are of a circle
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