<P> The mean orbital speed decreases with eccentricity . </P> <P> For the precise orbital speed of a body at any given point in its trajectory, both the mean distance and the precise distance are taken into account: </P> <Dl> <Dd> v = μ (2 r − 1 a) (\ displaystyle v = (\ sqrt (\ mu \ left ((2 \ over r) - (1 \ over a) \ right)))) </Dd> </Dl> <Dd> v = μ (2 r − 1 a) (\ displaystyle v = (\ sqrt (\ mu \ left ((2 \ over r) - (1 \ over a) \ right)))) </Dd>

Orbital period of a satellite is proportional to