<Dd> r h − x h . (\ displaystyle r (\ frac (h-x) (h)).) </Dd> <P> The surface area of the circular disk is then </P> <Dl> <Dd> π (r h − x h) 2 = π r 2 (h − x) 2 h 2 . (\ displaystyle \ pi \ left (r (\ frac (h-x) (h)) \ right) ^ (2) = \ pi r ^ (2) (\ frac ((h-x) ^ (2)) (h ^ (2))).) </Dd> </Dl> <Dd> π (r h − x h) 2 = π r 2 (h − x) 2 h 2 . (\ displaystyle \ pi \ left (r (\ frac (h-x) (h)) \ right) ^ (2) = \ pi r ^ (2) (\ frac ((h-x) ^ (2)) (h ^ (2))).) </Dd>

How do you find the volume of a container