<Dd> p (n) = 1 − p _̄ (n). (\ displaystyle p (n) = 1 - (\ bar (p)) (n).) </Dd> <P> The following table shows the probability for some other values of n (this table ignores the existence of leap years, as described above, as well as assuming that each birthday is equally likely): </P> <Dl> <Dd> <Table> <Tr> <Th> n </Th> <Th> p (n) </Th> </Tr> <Tr> <Td> </Td> <Td> 00.0% </Td> </Tr> <Tr> <Td> 5 </Td> <Td> 02.7% </Td> </Tr> <Tr> <Td> 10 </Td> <Td> 11.7% </Td> </Tr> <Tr> <Td> 20 </Td> <Td> 41.1% </Td> </Tr> <Tr> <Td> 23 </Td> <Td> 50.7% </Td> </Tr> <Tr> <Td> 30 </Td> <Td> 70.6% </Td> </Tr> <Tr> <Td> 40 </Td> <Td> 89.1% </Td> </Tr> <Tr> <Td> 50 </Td> <Td> 97.0% </Td> </Tr> <Tr> <Td> 60 </Td> <Td> 99.4% </Td> </Tr> <Tr> <Td> 70 </Td> <Td> 99.9% </Td> </Tr> <Tr> <Td> 75 </Td> <Td> 99.97% </Td> </Tr> <Tr> <Td> 100 </Td> <Td> 7001999999700000000 ♠ 99.999 97% </Td> </Tr> <Tr> <Td> 200 </Td> <Td> 7002100000000000000 ♠ 99.999 999 999 999 999 999 999 999 9998% </Td> </Tr> <Tr> <Td> 300 </Td> <Td> (100 − 6920600000000000000 ♠ 6 × 10)% </Td> </Tr> <Tr> <Td> 350 </Td> <Td> (100 − 6871300000000000000 ♠ 3 × 10)% </Td> </Tr> <Tr> <Td> 365 </Td> <Td> (100 − 6845145000000000000 ♠ 1.45 × 10)% </Td> </Tr> <Tr> <Td> 366 </Td> <Td> 100% </Td> </Tr> <Tr> <Td> 367 </Td> <Td> 100% </Td> </Tr> </Table> </Dd> </Dl> <Dd> <Table> <Tr> <Th> n </Th> <Th> p (n) </Th> </Tr> <Tr> <Td> </Td> <Td> 00.0% </Td> </Tr> <Tr> <Td> 5 </Td> <Td> 02.7% </Td> </Tr> <Tr> <Td> 10 </Td> <Td> 11.7% </Td> </Tr> <Tr> <Td> 20 </Td> <Td> 41.1% </Td> </Tr> <Tr> <Td> 23 </Td> <Td> 50.7% </Td> </Tr> <Tr> <Td> 30 </Td> <Td> 70.6% </Td> </Tr> <Tr> <Td> 40 </Td> <Td> 89.1% </Td> </Tr> <Tr> <Td> 50 </Td> <Td> 97.0% </Td> </Tr> <Tr> <Td> 60 </Td> <Td> 99.4% </Td> </Tr> <Tr> <Td> 70 </Td> <Td> 99.9% </Td> </Tr> <Tr> <Td> 75 </Td> <Td> 99.97% </Td> </Tr> <Tr> <Td> 100 </Td> <Td> 7001999999700000000 ♠ 99.999 97% </Td> </Tr> <Tr> <Td> 200 </Td> <Td> 7002100000000000000 ♠ 99.999 999 999 999 999 999 999 999 9998% </Td> </Tr> <Tr> <Td> 300 </Td> <Td> (100 − 6920600000000000000 ♠ 6 × 10)% </Td> </Tr> <Tr> <Td> 350 </Td> <Td> (100 − 6871300000000000000 ♠ 3 × 10)% </Td> </Tr> <Tr> <Td> 365 </Td> <Td> (100 − 6845145000000000000 ♠ 1.45 × 10)% </Td> </Tr> <Tr> <Td> 366 </Td> <Td> 100% </Td> </Tr> <Tr> <Td> 367 </Td> <Td> 100% </Td> </Tr> </Table> </Dd>

What is the chance of someone having the same birthday
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