<Dl> <Dd> v = ω r ≈ 3.0746 km / s ≈ 11 068 km / h ≈ 6877.8 mph . (\ displaystyle v = \ omega r \ approx 3.0746 ~ (\ text (km / s)) \ approx 11 \, 068 ~ (\ text (km / h)) \ approx 6877.8 ~ (\ text (mph)).) </Dd> </Dl> <Dd> v = ω r ≈ 3.0746 km / s ≈ 11 068 km / h ≈ 6877.8 mph . (\ displaystyle v = \ omega r \ approx 3.0746 ~ (\ text (km / s)) \ approx 11 \, 068 ~ (\ text (km / h)) \ approx 6877.8 ~ (\ text (mph)).) </Dd> <P> By the same formula, we can find the geostationary - type orbit of an object in relation to Mars (this type of orbit above is referred to as an areostationary orbit if it is above Mars). The geocentric gravitational constant GM (which is μ) for Mars has the value of 42,828 km s, and the known rotational period (T) of Mars is 88,642.66 seconds . Since ω = 2π / T, using the formula above, the value of ω is found to be approx 7.088218 × 10 s . Thus r = 8.5243 × 10 km, whose cube root is 20,427 km; subtracting the equatorial radius of Mars (3396.2 km), we have 17,031 km . </P>

Angular speed of a satellite in geosynchronous orbit