<Li> More generally, if (p, q) is a solution, then it is possible to generate a sequence of solutions (p, q) satisfying: </Li> <Dl> <Dd> <Dl> <Dd> p m + n = p m p n + S ⋅ q m q n (\ displaystyle p_ (m + n) = p_ (m) p_ (n) + S \ cdot q_ (m) q_ (n) \, \!) </Dd> <Dd> q m + n = p m q n + p n q m (\ displaystyle q_ (m + n) = p_ (m) q_ (n) + p_ (n) q_ (m) \, \!) </Dd> </Dl> </Dd> </Dl> <Dd> <Dl> <Dd> p m + n = p m p n + S ⋅ q m q n (\ displaystyle p_ (m + n) = p_ (m) p_ (n) + S \ cdot q_ (m) q_ (n) \, \!) </Dd> <Dd> q m + n = p m q n + p n q m (\ displaystyle q_ (m + n) = p_ (m) q_ (n) + p_ (n) q_ (m) \, \!) </Dd> </Dl> </Dd> <Dl> <Dd> p m + n = p m p n + S ⋅ q m q n (\ displaystyle p_ (m + n) = p_ (m) p_ (n) + S \ cdot q_ (m) q_ (n) \, \!) </Dd> <Dd> q m + n = p m q n + p n q m (\ displaystyle q_ (m + n) = p_ (m) q_ (n) + p_ (n) q_ (m) \, \!) </Dd> </Dl>

What is the method of finding square root