<Dd> T = 1 2 a b (\ displaystyle T = (\ tfrac (1) (2)) ab) </Dd> <P> where a and b are the legs of the triangle . </P> <P> If the incircle is tangent to the hypotenuse AB at point P, then denoting the semi-perimeter (a + b + c) / 2 as s, we have PA = s − a and PB = s − b, and the area is given by </P> <Dl> <Dd> T = PA ⋅ PB = (s − a) (s − b). (\ displaystyle T = (\ text (PA)) \ cdot (\ text (PB)) = (s-a) (s-b).) </Dd> </Dl>

What is the area of a right-angled triangle
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