<Dl> <Dd> 1) x 2 + 2 x − 2 = 0 (\ displaystyle 1) \ x ^ (2) + 2x - 2 = 0) </Dd> <Dd> 2) x 2 + 2 x = 2 (\ displaystyle 2) \ x ^ (2) + 2x = 2) </Dd> <Dd> 3) x 2 + 2 x + 1 = 2 + 1 (\ displaystyle 3) \ x ^ (2) + 2x + 1 = 2 + 1) </Dd> <Dd> 4) (x + 1) 2 = 3 (\ displaystyle 4) \ \ left (x + 1 \ right) ^ (2) = 3) </Dd> <Dd> 5) x + 1 = ± 3 (\ displaystyle 5) \ x + 1 = \ pm (\ sqrt (3))) </Dd> <Dd> 6) x = − 1 ± 3 (\ displaystyle 6) \ x = - 1 \ pm (\ sqrt (3))) </Dd> </Dl> <Dd> 1) x 2 + 2 x − 2 = 0 (\ displaystyle 1) \ x ^ (2) + 2x - 2 = 0) </Dd> <Dd> 2) x 2 + 2 x = 2 (\ displaystyle 2) \ x ^ (2) + 2x = 2) </Dd> <Dd> 3) x 2 + 2 x + 1 = 2 + 1 (\ displaystyle 3) \ x ^ (2) + 2x + 1 = 2 + 1) </Dd>

What is a solution in a quadratic equation