<P> Let gas 1 be H and gas 2 be O . (This example is solving for the ratio between the rates of the two gases) </P> <Dl> <Dd> Rate H 2 Rate O 2 = 32 2 = 16 1 = 4 1 (\ displaystyle ((\ mbox (Rate H)) _ (2) \ over (\ mbox (Rate O)) _ (2)) = ((\ sqrt (32)) \ over (\ sqrt (2))) = ((\ sqrt (16)) \ over (\ sqrt (1))) = (\ frac (4) (1))) </Dd> </Dl> <Dd> Rate H 2 Rate O 2 = 32 2 = 16 1 = 4 1 (\ displaystyle ((\ mbox (Rate H)) _ (2) \ over (\ mbox (Rate O)) _ (2)) = ((\ sqrt (32)) \ over (\ sqrt (2))) = ((\ sqrt (16)) \ over (\ sqrt (1))) = (\ frac (4) (1))) </Dd> <P> Therefore, hydrogen molecules effuse four times faster than those of oxygen . </P>

State and explain graham's law of diffusion of gases