<Dd> π r 2 h 2 ∫ 0 h (h − x) 2 d x (\ displaystyle (\ frac (\ pi r ^ (2)) (h ^ (2))) \ int _ (0) ^ (h) (h-x) ^ (2) dx) </Dd> <P> Integrating gives us </P> <Dl> <Dd> π r 2 h 2 (h 3 3) = 1 3 π r 2 h . (\ displaystyle (\ frac (\ pi r ^ (2)) (h ^ (2))) \ left ((\ frac (h ^ (3)) (3)) \ right) = (\ frac (1) (3)) \ pi r ^ (2) h .) </Dd> </Dl> <Dd> π r 2 h 2 (h 3 3) = 1 3 π r 2 h . (\ displaystyle (\ frac (\ pi r ^ (2)) (h ^ (2))) \ left ((\ frac (h ^ (3)) (3)) \ right) = (\ frac (1) (3)) \ pi r ^ (2) h .) </Dd>

Why is the volume of a regularly shaped solid usually cm3