<Dl> <Dd> A B = ⋃ i ≥ 1 (∩ j <i B j _̄, A i B i) (\ displaystyle A_ (B) = \ bigcup _ (i \ geq 1) (\ bigl () (\ underset (j <i) (\ cap)) (\ overline (B_ (j))), A_ (i) B_ (i) (\ bigr))) </Dd> </Dl> <Dd> A B = ⋃ i ≥ 1 (∩ j <i B j _̄, A i B i) (\ displaystyle A_ (B) = \ bigcup _ (i \ geq 1) (\ bigl () (\ underset (j <i) (\ cap)) (\ overline (B_ (j))), A_ (i) B_ (i) (\ bigr))) </Dd> <P> It can be shown that </P> <Dl> <Dd> P (A B) = P (A ∩ B) P (B) (\ displaystyle P (A_ (B)) = (\ frac (P (A \ cap B)) (P (B)))) </Dd> </Dl>

According to the general equation for conditional probability of and what is a. b. c. d