<Dl> <Dd> x 2 + 1 × 10 − 5 x − 1 × 10 − 6 = 0 (\ displaystyle x ^ (2) + 1 \ times 10 ^ (- 5) x-1 \ times 10 ^ (- 6) = 0) </Dd> </Dl> <Dd> x 2 + 1 × 10 − 5 x − 1 × 10 − 6 = 0 (\ displaystyle x ^ (2) + 1 \ times 10 ^ (- 5) x-1 \ times 10 ^ (- 6) = 0) </Dd> <P> which gives x = 9.95 × 10 M and a pH = 3.00 . The simplified method gives </P> <Dl> <Dd> pH = − log ⁡ 10 − 5 ⋅ 0.1 = 3.00 (\ displaystyle ((\ ce (pH))) = - \ log (\ sqrt (10 ^ (- 5) \ cdot 0.1)) = 3.00) </Dd> </Dl>

Why is nitric acid described as a strong acid