<Tr> <Td> 6 </Td> <Td> α (\ displaystyle \ alpha) a </Td> <Td> ← β (\ displaystyle \ beta) b </Td> <Td> γ (\ displaystyle \ gamma) c </Td> </Tr> <Tr> <Td> 7 </Td> <Td> ab </Td> <Td> α (\ displaystyle \ alpha) β (\ displaystyle \ beta) → </Td> <Td> γ (\ displaystyle \ gamma) c </Td> </Tr> <Tr> <Td> 8 </Td> <Td> ab </Td> <Td> ← c </Td> <Td> α (\ displaystyle \ alpha) β (\ displaystyle \ beta) γ (\ displaystyle \ gamma) </Td> </Tr> <Tr> <Td> 9 </Td> <Td> </Td> <Td> ac → </Td> <Td> α (\ displaystyle \ alpha) β (\ displaystyle \ beta) γ (\ displaystyle \ gamma) </Td> </Tr>

How to solve the puzzle of 3 cannibals and 3 missionaries