<Dd> E n = 2 ħ 2 v n 2 m L 2 (\ displaystyle E_ (n) = (2 \ hbar ^ (2) v_ (n) ^ (2) \ over mL ^ (2))). </Dd> <P> If we want, we can go back and find the values of the constants A, B, G, H (\ displaystyle A, B, G, H) in the equations now (we also need to impose the normalisation condition). On the right we show the energy levels and wave functions in this case (where x 0 ≡ ħ / 2 m V 0 (\ displaystyle x_ (0) \ equiv \ hbar / (\ sqrt (2mV_ (0))))): </P> <P> We note that however small u 0 (\ displaystyle u_ (0)) is (however shallow or narrow the well), there is always at least one bound state . </P> <P> Two special cases are worth noting . As the height of the potential becomes large, V 0 → ∞ (\ displaystyle V_ (0) \ to \ infty), the radius of the semicircle gets larger and the roots get closer and closer to the values v n = n π / 2 (\ displaystyle v_ (n) = n \ pi / 2), and we recover the case of the infinite square well . </P>

Where are the boundaries of the potential well the left boundary is at x =