<Dd> p (n) ≈ n 2 2 m (\ displaystyle p (n) \ approx (n ^ (2) \ over 2m)) </Dd> <P> which can also be written as </P> <Dl> <Dd> n ≈ 2 m × p (n) (\ displaystyle n \ approx (\ sqrt (2m \ times p (n)))) </Dd> </Dl> <Dd> n ≈ 2 m × p (n) (\ displaystyle n \ approx (\ sqrt (2m \ times p (n)))) </Dd>

What is the chance of having the same birthday