<P> For maximum range, this results in the following equation: </P> <Dl> <Dd> tan 2 ⁡ ψ = 2 g y 0 + v 2 v 2 = C + 1 (\ displaystyle \ tan ^ (2) \ psi = (\ frac (2gy_ (0) + v ^ (2)) (v ^ (2))) = C + 1) </Dd> </Dl> <Dd> tan 2 ⁡ ψ = 2 g y 0 + v 2 v 2 = C + 1 (\ displaystyle \ tan ^ (2) \ psi = (\ frac (2gy_ (0) + v ^ (2)) (v ^ (2))) = C + 1) </Dd> <P> Rewriting the original solution for θ, we get: </P>

How to calculate theoretical range in projectile motion