<Ul> <Li> with acid: Be (OH) + 2 HCl → BeCl + 2 H O </Li> <Li> with base: Be (OH) + 2 NaOH → Na (Be (OH)). </Li> </Ul> <Li> with acid: Be (OH) + 2 HCl → BeCl + 2 H O </Li> <Li> with base: Be (OH) + 2 NaOH → Na (Be (OH)). </Li>

Does ammonia or naoh provide a more conclusive demonstration of amphoterism