<Dl> <Dd> <Dl> <Dd> V T = V 0 + (1 273 × V 0) × T (\ displaystyle V_ (T) = V_ (0) + ((\ tfrac (1) (273)) \ times V_ (0)) \ times T) </Dd> </Dl> </Dd> </Dl> <Dd> <Dl> <Dd> V T = V 0 + (1 273 × V 0) × T (\ displaystyle V_ (T) = V_ (0) + ((\ tfrac (1) (273)) \ times V_ (0)) \ times T) </Dd> </Dl> </Dd> <Dl> <Dd> V T = V 0 + (1 273 × V 0) × T (\ displaystyle V_ (T) = V_ (0) + ((\ tfrac (1) (273)) \ times V_ (0)) \ times T) </Dd> </Dl> <Dd> V T = V 0 + (1 273 × V 0) × T (\ displaystyle V_ (T) = V_ (0) + ((\ tfrac (1) (273)) \ times V_ (0)) \ times T) </Dd>

Why should we use the same charles law apparatus at all four different temperatures