<P> Under certain assumptions (uniform material, uniform magnetic field, no skin effect, etc .) the power lost due to eddy currents per unit mass for a thin sheet or wire can be calculated from the following equation: </P> <Dl> <Dd> P = π 2 B p 2 d 2 f 2 6 k ρ D, (\ displaystyle P = (\ frac (\ pi ^ (2) B_ (\ text (p)) ^ (\, 2) d ^ (2) f ^ (2)) (6k \ rho D)),) </Dd> </Dl> <Dd> P = π 2 B p 2 d 2 f 2 6 k ρ D, (\ displaystyle P = (\ frac (\ pi ^ (2) B_ (\ text (p)) ^ (\, 2) d ^ (2) f ^ (2)) (6k \ rho D)),) </Dd> <Dl> <Dd> P is the power lost per unit mass (W / kg), </Dd> <Dd> B is the peak magnetic field (T), </Dd> <Dd> d is the thickness of the sheet or diameter of the wire (m), </Dd> <Dd> f is the frequency (Hz), </Dd> <Dd> k is a constant equal to 1 for a thin sheet and 2 for a thin wire, </Dd> <Dd> ρ is the resistivity of the material (Ω m), and </Dd> <Dd> D is the density of the material (kg / m). </Dd> </Dl>

Give at least two examples of application of eddy currents