<Dd> x = v 0 t cos ⁡ (θ) (\ displaystyle x = v_ (0) t \ cos (\ theta)), </Dd> <Dd> y = v 0 t sin ⁡ (θ) − 1 2 g t 2 (\ displaystyle y = v_ (0) t \ sin (\ theta) - (\ frac (1) (2)) gt ^ (2)). </Dd> <P> The magnitude of the displacement is: </P> <Dl> <Dd> Δ r = x 2 + y 2 (\ displaystyle \ Delta r = (\ sqrt (x ^ (2) + y ^ (2) \))). </Dd> </Dl>

What is the formula for maximum height in projectile