<Dd> z = r 2 − x 2 (\ displaystyle z = (\ sqrt (r ^ (2) - x ^ (2)))) </Dd> <P> where y or z can be taken to represent the radius of a disk at a particular x value . </P> <P> Using y as the disk radius, the volume of the sphere can be calculated as </P> <Dl> <Dd> ∫ − r r π y 2 d x = ∫ − r r π (r 2 − x 2) d x . (\ displaystyle \ int _ (- r) ^ (r) \ pi y ^ (2) \, dx = \ int _ (- r) ^ (r) \ pi \ left (r ^ (2) - x ^ (2) \ right) \, dx .) </Dd> </Dl>

How can you find the volume of a liquid