<P> When the second equation is used to express the work as a difference in heats, we get </P> <Dl> <Dd> Q H − Q C <(1 − T C T H) Q H (\ displaystyle Q_ (H) - Q_ (C) <\ left (1 - (\ frac (T_ (C)) (T_ (H))) \ right) Q_ (H)) </Dd> <Dd> or </Dd> <Dd> Q C> T C T H Q H (\ displaystyle Q_ (C)> (\ frac (T_ (C)) (T_ (H))) Q_ (H)) </Dd> </Dl> <Dd> Q H − Q C <(1 − T C T H) Q H (\ displaystyle Q_ (H) - Q_ (C) <\ left (1 - (\ frac (T_ (C)) (T_ (H))) \ right) Q_ (H)) </Dd> <Dd> Q C> T C T H Q H (\ displaystyle Q_ (C)> (\ frac (T_ (C)) (T_ (H))) Q_ (H)) </Dd>

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