<Dl> <Dd> Δ θ = 0.5 ∘ × (60 × 2 − 11 × 20) = 0.5 ∘ × (120 − 220) = 50 ∘ (\ displaystyle (\ begin (aligned) \ Delta \ theta & = \ vert 0.5 ^ (\ circ) \ times (60 \ times 2 - 11 \ times 20) \ vert \ \ & = \ vert 0.5 ^ (\ circ) \ times (120 - 220) \ vert \ \ & = 50 ^ (\ circ) \ end (aligned))) </Dd> </Dl> <Dd> Δ θ = 0.5 ∘ × (60 × 2 − 11 × 20) = 0.5 ∘ × (120 − 220) = 50 ∘ (\ displaystyle (\ begin (aligned) \ Delta \ theta & = \ vert 0.5 ^ (\ circ) \ times (60 \ times 2 - 11 \ times 20) \ vert \ \ & = \ vert 0.5 ^ (\ circ) \ times (120 - 220) \ vert \ \ & = 50 ^ (\ circ) \ end (aligned))) </Dd> <P> The time is 10: 16 . </P> <Dl> <Dd> Δ θ = 0.5 ∘ × (60 × 10 − 11 × 16) = 0.5 ∘ × (600 − 176) = 212 ∘ (> 180 ∘) = 360 ∘ − 212 ∘ = 148 ∘ (\ displaystyle (\ begin (aligned) \ Delta \ theta & = \ vert 0.5 ^ (\ circ) \ times (60 \ times 10 - 11 \ times 16) \ vert \ \ & = \ vert 0.5 ^ (\ circ) \ times (600 - 176) \ vert \ \ & = 212 ^ (\ circ) \ \ (> 180 ^ (\ circ)) \ \ & = 360 ^ (\ circ) - 212 ^ (\ circ) \ \ & = 148 ^ (\ circ) \ end (aligned))) </Dd> </Dl>

What is the angle between the hands of a clock at 9.30