<P> When calculating an allele frequency for a diploid species, remember that homozygous individuals have two copies of an allele, whereas heterozygotes have only one . In our example, each of the 42 pink - flowered heterozygotes has one copy of the a allele, and each of the 9 white - flowered homozygotes has two copies . Therefore, the allele frequency for a (the white color allele) equals </P> <Dl> <Dd> f (a) = (A a) + 2 × (a a) 2 × (A A) + 2 × (A a) + 2 × (a a) = 42 + 2 × 9 2 × 49 + 2 × 42 + 2 × 9 = 60 200 = 0.3 (\ displaystyle (\ begin (aligned) f ((a)) & = ((Aa) + 2 \ times (aa) \ over 2 \ times (AA) + 2 \ times (Aa) + 2 \ times (aa)) = (42 + 2 \ times 9 \ over 2 \ times 49 + 2 \ times 42 + 2 \ times 9) = (60 \ over 200) = 0.3 \ \ \ end (aligned))) </Dd> </Dl> <Dd> f (a) = (A a) + 2 × (a a) 2 × (A A) + 2 × (A a) + 2 × (a a) = 42 + 2 × 9 2 × 49 + 2 × 42 + 2 × 9 = 60 200 = 0.3 (\ displaystyle (\ begin (aligned) f ((a)) & = ((Aa) + 2 \ times (aa) \ over 2 \ times (AA) + 2 \ times (Aa) + 2 \ times (aa)) = (42 + 2 \ times 9 \ over 2 \ times 49 + 2 \ times 42 + 2 \ times 9) = (60 \ over 200) = 0.3 \ \ \ end (aligned))) </Dd> <P> This result tells us that the allele frequency of a is 0.3 . In other words, 30% of the alleles for this gene in the population are the a allele . </P>

If the expected allele frequencies are equal what are the expected genotype frequencies