<Dl> <Dd> M F = 3 5 (\ displaystyle M_ (F) = (\ tfrac (3) (5))) </Dd> </Dl> <Dd> M F = 3 5 (\ displaystyle M_ (F) = (\ tfrac (3) (5))) </Dd> <P> Knowing that M F + M O = 1 (\ displaystyle M_ (F) + M_ (O) = 1), we deduce: </P> <Dl> <Dd> M O = 1 − 3 5 = 2 5 (\ displaystyle M_ (O) = 1 - (\ tfrac (3) (5)) = (\ tfrac (2) (5))) </Dd> <Dd> W F = 2 3 M F = 2 5 (\ displaystyle W_ (F) = (\ tfrac (2) (3)) M_ (F) = (\ tfrac (2) (5))) </Dd> <Dd> W O = 1 − 2 5 = 3 5 (\ displaystyle W_ (O) = 1 - (\ tfrac (2) (5)) = (\ tfrac (3) (5))) </Dd> </Dl>

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